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Matches 1 to 5 of 5 for First Name equals JOE AND Tree equals adkinshorton

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#	Last Name, Given Name(s)	Person ID	Born/Christened	Location
1	Vickers, Joe	I2007
2	Seink, Joe	I11318
3	Schuler, Joe	I7944
4	Pokorny, Joe	I17361	b. Est 1869	Milevska, Pisek, Bohemia
5	Hadden, Joe	I13016

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